ON Semiconductor 2N6040

2N6040 Overview
The DC current gain is the ratio of the base current to the collector current βdc = Ic/Ib and the DC current gain for this device is 1000 @ 4A 4V.With a collector emitter saturation voltage of 2V, it offers maximum design flexibility.Vce saturation means Ic is at its maximum value(saturated), and the vce saturation(Max) is 2V @ 16mA, 4A.In order to achieve high efficiency, the continuous collector voltage should be kept at 8A.If the emitter base voltage is kept at 5V, a high level of efficiency can be achieved.In definition, current rating refers to the maximum current a fuse can carry for an indefinite period without deteriorating too much, and the current rating of this device is -8A.A transition frequency of 4MHz is present in the part.Collector current can be as low as 8A volts at its maximum.

2N6040 Features
the DC current gain for this device is 1000 @ 4A 4V
a collector emitter saturation voltage of 2V
the vce saturation(Max) is 2V @ 16mA, 4A
the emitter base voltage is kept at 5V
the current rating of this device is -8A
a transition frequency of 4MHz


2N6040 Applications
There are a lot of ON Semiconductor
2N6040 applications of single BJT transistors.


Inverter
Interface
Driver
Muting